COMMUTABILITY OF ELEMENTS IN D2n

If n=2k is even and n>=4, then rk is an element of order 2 which commutes with all elements of D2n. Also, rk is the only nonidentity element of D2n which commutes with all elements of D2n.

PROOF:
  • rk is an element of order 2 which commutes with all elements of D2n.
    rn=1 --> r2k=1
    Therefore rk is an element of order 2. |rk|=2

    To show commutability, break into two cases:
    • let ri be an element in D2n. Then (rk)(ri) = rk+i = ri+k = (ri)(rk)
    • Let ris be an element in D2n. Then (ris)(rk) = ri(srks)s = rir-ks = rk(ris).
  • Suppose some element x of D2n commutes with every other element.
    • suppose x=ri. Then xs=sx => ris = sri = r-i => ri = r-i => r2i=1, so i=k.

    Now suppose n is odd. Argue as above with x=sri and x=ri. If x=sri, then r2=1 which is not possible. If x=ri we get r2i=1 which is also not possible as then either n|2i or n|i as n is odd, so x=1. Therefore, if n is odd, only the identity commutes with all elements in D2n