This is a way to write a straight line equation to easily determine the slope of the line, and the y-intercept of it.

The form is: y=mx+b where m is the slope, and b is the y-intercept.

The reason this works is pretty easy. If our slope is two, then for every increment to x, y is incremented twice (slope is rise over run). So, if point (0,0) is on the line, then (1,2), (2,4), and (3,6) are on the line. Y is always equal to twice x.

You add the y-intercept (b) because, if we a line with a slope of two, and (0,1) is on the line, the points are the same as those on the line above, but for every x value, y is the same **plus one**. We have (1,2+1), (2,4+1), and (3,6+1). When the y-intercept changes, we are in effect dragging our line up and down on the y-axis.

## Finding the equation from a graph

Pick two points. Find rise/run (y_{1}-y_{2}/x_{1}-x_{2}). That's your slope, and therefore your m value.

Next, go to x=0. Whatever the y value is for x=0 is the y-intercept is your b value.

Plug `em in, and you have your equation.

## I know a point, and the slope. How do I get my y-intercept?

Let's say that we have point (2,3) and a slope of 4. We then know that:

x=2

y=3

m=4

We substitute into the equation and solve:

(3)=(4)(2)+b

3=8+b

-5=b

## I know a point and the y-intercept. What's the slope?

We'll stick with the line from the previous example:

x=2

y=3

b=-5

Substitution and solving again:

(3)=m(2)+(-5)

3=m*2-5

8=m*2

4=m

## I have my equation, now I need points. How do I get them?

Again, taking the same line as before, we have: y=4x-5

Just choose a value for x (zero is a good place to start) and solve for y.

y=4(0)-5

y=-5

Then, keep changing the value for x until you have enough points:

y=4(1)-5

y=4-5

y=-1

y=4(2)-5

y=8-5

y=3