weetos

I have such a way.*

The Game

The Game is very simple: get some Weetos, and munch away. Once you are down to a countably small number of Weetos, the Game begins. First eat one Weeto. Then two at a time. Then three, and so on, until you have run out of Weetos. The aim of the game is to get a "Perfect!" as deemed by the program, which means that on your last spoonful, you will finish your bowl by eating exactly the number of Weetos that you are supposed to (e.g. if your last spoonful was 4, and there are 5 left, you get a "Perfect!"). Non-Perfect scores are punishable by death, or a re-match. The program will also tell you what the maximum number of Weetos on your spoon will be, and the number on your last spoonful.

Give me the Code. Also, shut up

#include <stdio.h>

int main ()
{
  int have, need;

  printf("Please enter the number of remaining Weetos and don't cry about it: \n");
  scanf("%d", &have);

  need = 0;
	
  while(have>0)
  {
    need++;                     /* Number needed */
    have = have - need;   /* Eat number of Weetos needed */
  }

  if(have >= 0)
  {
    printf("Need = %d\t Have = %d\n", need, have);

    if(need == have)
    {
      printf("Perfect! The largest, and last, spoonful will have %d Weetos.\n", need);
    }

    else if(need > have)
    {
      if(need==1)
      {
        printf("The largest spoonful will have %d Weeto, and the last spoonful will have %d Weetos. \n", need, have+need);
      }	
      else
      {
      printf("The largest spoonful will have %d Weetos, and the last spoonful will have %d Weetos. \n", need, have+need);
      }
    }
  }
	
  else
  {
    if(need<=2)
    {
      printf("The largest spoonful will have %d Weeto, and the last spoonful will have %d Weeto.\n", need-1, have+need);
    }		
    else
    {
      printf("The largest spoonful will have %d Weetos, and the last spoonful will have %d Weetos.\n", need-1, have+need);
    }
  }	
exit(0);
}