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Elements I.12

created by Xeno_Paradox

(thing) by Xeno_Paradox (7.8 y) (print)   ?   (I like it!) Sat Aug 19 2000 at 16:33:31

Euclid's Elements: Book I: Proposition 12

Proposition 12: To a given infinite straight line, from a given point which is not on it, to draw a perpendicular straight line.

Let AB be the given infinite straight line, and C the given point which is not on it;

thus it is required to draw to the given infinite straight line AB, from the given point C which is not on it, a perpendicular straight line.

For let a point D be taken at random on the other side of the straight line AB, and with centre C and distance CD let the circle EFG be described; Post. 3 let the straight line EG be bisected at H, I. 10 and let the straight lines CG, CH, CE be joined. Post. 1

I say that CH has been drawn perpendicular to the given infinite straight line AB from the given point C which is not on it.

For, since GH is equal to HE, and HC is common, the two sides GH, HC are equal to the two sides EH, HC respectively; and the base CG is equal to the base CE; therefore the angle CHG is equal to the angle EHC. I. 8 And they are adjacent angles.

But, when a straight line set up on a straight line makes the adjacent angles equal to one another, each of the equal angles is right, and the straight line standing on the other is called a perpendicular to that on which it stands. Def. 10

Therefore CH has been drawn perpendicular to the given infinite straight line AB from the given point C which is not on it.

Q.E.F.


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Elements I.13 Elements I.11 Euclid's Elements: Book I
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